先化简,再求值：[x+2/（x^2-2x）-(x-1）/（x^2-4x+4)]÷2x-8/(x^3-2x^2)

原式=[(x+2)/(x^2-2x) - (x-1)/(x^2-4x+4)]÷2(x-4)/(x^3-2x^2)
=[(x+2)/(x^2-2x) - (x-1)/(x-2)²)]* [x²(x-2)]/2(x-4)
=[(x+2)- x(x-1)/(x-2)]*x/2(x-4)
=[(x²-4-x²+x)/(x-2)]*x/2(x-4)
=[(x-4)/(x-2)]*x/2(x-4)
=x/2(x-2)
x≥0
x-2≤6
x≤8
解集为0≤x≤8
x=1时,原式=1/2*(-1)=-1/2